Monday, August 14, 2017

Why C Sharp Supports Multiple Inheritance with Interface only.

Multiple Inhertiance

A class which derived from more than one class it is called Multiple inheritance

-----------------------------------------------------------------------------------------
Example:


public class Employee
    {
        public virtual void DoWork()
        {
            //Do work
        }
    }

    public class Manager:Employee
    {
        public override void DoWork()
        {
            //Manager's implementation of do work
        }
    }

    public class Developer : Employee
    {
        public override void DoWork()
        {
            //Deveoper's implementation of do work
        }
    }

    public class JuniorDeveloper:Manager, Developer// Compile Time Error :Cannot have multiple base classes but assume that it were possible
    { }


----------------------------------------------------------------------------------


public class A
    {
        public virtual void A_Method()
        {
            Console.WriteLine("Class A Method");
        }
    }

    public class B : A
    {
        public override void A_Method()
        {
            Console.WriteLine("Class B Method");
        }
    }

    public class C : A
    {
        public override void A_Method()
        {
            Console.WriteLine("Class C Method");
        }
    }

    public class D : B, C  // If Multiple inheritence is possible in C# then
    {
        public override void A_Method()
        {
            Console.WriteLine("Class C Method");
        }
    }


    public static void main()
    {
        D objD = new D();
        objD.A_Method();// Making object of class D and calling overloaded method A_method will 
                        //confuse the compiler which class method to call as both inherited class methods has been overloaded.
    }

Explanation:
In the code above we have the A_Method()
which is defined by class A. But, the problem is that class D derives from both classes B and C, which both derive from class A. This means that there are essentially 2 copies of the A_Method()
that are available because there are 2 instances of A in D’s class hierarchy.
And the compiler will give an error and say that the reference to A_Method() is ambiguous.

-------------------------------------------------------------------------------------

Step1 Interface Definition

public interface IEmployee
{
   string GetEmployeeId();
}
The above code contains a method signature named DoWork ().
 Step 2 : Interface Implementation
As I have already defined an interface IEmployee in the above code snippet. Now if I want to implement the interface to my class Engineer as shown below.
public class Engineer:IEmployee
{

}
Step 3: 

Now if I execute the above code I will get a compile time error


-----------------------------------------------------------------------------------



Step 4:

The correct implementation of the above code is shown below



As we can see from the above code the signature of the GetEmployeeId() method in the Engineer class is same as the signature of the method in the (IEmployee)Interface.

Step 5:
Interface can only “inherit” from the interface only. Suppose if we want to extend the implementation of an interface in some part of our project without disturbing the already existing interface, in that case we can create a new interface and inherit it into new interface as shown below.

Example:

public interface Ibase1
    {
        void message();
    }
    public interface Ibase2
    {
        void message();
    }
    public class child : Ibase1, Ibase2
    {
        public void message()
        {
            Console.WriteLine("Hello Multiple Inheritance");
        }
    }

    class Program
    {
        static void Main(string[] args)
        {
            child obj = new child();
            obj.message();
            Console.ReadLine();
        }
    }


Output:


Important Points to Remembers 
    Class FirstClass { }
    Class SecondClass { }

interface X { }
interface Y { }
You can inherit like the following:

class NewClass : X, Y { }
In the above code, the class "NewClass" is created from multiple interfaces.


class NewClass : FirstClass, X { }
In the above code, the class "NewClass" is created from interface X and class "FirstClass".

WRONG:

class NewClass : FirstClass, SecondClass  { }
C# doesn't support Multiple inheritance

The above code is wrong in C# because the new class is created from class "FirstClass" and class "SecondClass". The reason is that C# does not allows multiple inheritance.



Finally Note: 
Point 1: 
When we use the Multiple inheritance , we use more than one class. Lets  us Assume one condition  like below
class A and class B are base classes and class c is is multiple inherting it and where class c is inheriting a function ,ok it may be possible that this function with same name and same signature can present in both class A and Class B .That time how the compiler will know that which function it should take wheather from class A or class B.
So this time Multiple inheritanc won't work .So avoiding this problem we use Interface. In interface we just declare a function  and in derived class we write the implemenation.

Point 2:
C# does not allow multiple inheritance because of ambiguity.



Thursday, August 10, 2017

How to create crystal Reports with MVC.

Visual Studio 2015 installation will not have Crystal Reports and hence we need to  install it you can download it from the following location

Download Link



After downloading the link. Click on Open  and follow the below steps .






After installation of Crystal Reports. Let us start working on the example.
Go to Visual Studio

File-> New-Project



After clicking on ok , the below screen gets displayed: 

Select Empty and select the check box MVC




Configuring and connecting Entity Framework to database

Go to App Data to Add the DataBase as shown below

App Data--->Add--> New Item--> Sql Server DataBase 




In the visual Studio in the solution explorer you can find as shown below



Click on the Open,  the below screen gets displayed  and select New Query and execute the below script  to create the table




Script: 

CREATE TABLE [dbo].[EmployeeInfo] (
    [EmpNo]       INT          IDENTITY (1, 1) NOT NULL,
    [EmpName]     VARCHAR (50) NOT NULL,
    [Salary]      INT          NOT NULL,
    [DeptName]    VARCHAR (50) NOT NULL,
    [Designation] VARCHAR (50) NOT NULL,
    [HRA]         AS           ([Salary]*(0.2)),
    [TA]          AS           ([Salary]*(0.15)),
)

Now the table has been created , 

Go To Model Folder

Add-->New Item-->ADO.NET Entity Data Model




Give any Name and click on Add, the below screen will be displayed






And Click On Finish

Controller:

public class CrstalReportExampleController : Controller
    {
        // GET: CrstalReportExample
        public ActionResult Index()
        {
            EmployeeModel emp = new EmployeeModel();
            return View(from employee in emp.EmployeeInfoes.Take(10)
                        select employee);
        }
    }

Index.cs.html

<html>
<body>
    <h4>Employees</h4>
    <hr />
    <table cellpadding="0" cellspacing="0">
        <tr>
            <th>Employee Id</th>
            <th>Employee Name</th>
            <th>DeptName</th>  
            <th>Designation</th>  
           
        </tr>
        @foreach (WebApplication1.Models.EmployeeInfo employee in Model)
        {
            <tr>
                <td>@employee.EmpNo</td>
                <td>@employee.EmpName</td>
                <td>@employee.DeptName</td>
                <td>@employee.Designation</td>
            </tr>
        }
    </table>
    <br />
    <a href="~/Reports/WebForm1.aspx">View Report</a>
</body>
</html>

Create a new folder with the name Reports 





Right click on the folder Reports -Select -->Add-->New Item



Click on Add button

Select Standard Button as shown below



Once you press OK in the above screen  dialog, the Report Wizard starts and you get the following dialog where you need to choose the type of Database connection for your Crystal Report. 


Click on Next Button


Choose the columns which you want to display in the reports as shown below



After Clicking on Finish button the below screen gets displayed




Note now, Crystal Report works only with a Crystal Report Viewer control which is available only in ASP.Net Web Forms and hence for displaying a Crystal Report, you will need to add a Web Forms page.

Go to Reports Folder and Select Add--> New Item--> 



Now in this web form we need to add  Crystal Report Viewer control from the ToolBox as shown below




WebForm.aspx( Create this form in the Reports Folder).

<html xmlns="http://www.w3.org/1999/xhtml">
<head runat="server">
    <title></title>
</head>
<body>
    <form id="form1" runat="server">
    <div>
    
    </div>
        <CR:CrystalReportViewer ID="CrystalReportViewer1" runat="server" AutoDataBind="true" Height="450" Width="650"/>

    </form>
</body>
</html>


.cs

 private EmployeeModel context = new EmployeeModel();
        protected void Page_Load(object sender, EventArgs e)
        {

            
            CrystalReportViewer1.ToolPanelView = CrystalDecisions.Web.ToolPanelViewType.None;
            CrystalReport1 crystalReport = new CrystalReport1();
            List<EmployeeInfo> allemps = new List<EmployeeInfo>();
            allemps = context.EmployeeInfoes.ToList();

            crystalReport.SetDataSource(allemps);
            CrystalReportViewer1.ReportSource = crystalReport;
            //Response.Buffer = false;
            Response.ClearContent();
            //Response.ClearHeaders();
        }


Output:



After clicking on view Report



2 Example :

You can display the same report in another way as shown below

Modify the Controller code as shown below

private EmployeeModel context = new EmployeeModel();
        // GET: CrstalReportExample
        public ActionResult Index()
        {
            EmployeeModel emp = new EmployeeModel();
            return View(from employee in emp.EmployeeInfoes.Take(10)
                        select employee);
        }

        public ActionResult ExportCustomers()
        {

            List<EmployeeInfo> allemps = new List<EmployeeInfo>();
            allemps = context.EmployeeInfoes.ToList();


            ReportDocument rd = new ReportDocument();
            rd.Load(Path.Combine(Server.MapPath("~/Reports"), "CrystalReport1.rpt"));

            rd.SetDataSource(allemps);

            Response.Buffer = false;
            Response.ClearContent();
            Response.ClearHeaders();


            Stream stream = rd.ExportToStream(CrystalDecisions.Shared.ExportFormatType.PortableDocFormat);
            stream.Seek(0, SeekOrigin.Begin);
            return File(stream, "application/pdf", "EmployeeList.pdf");
        }

In the index.cs.html add the below line


<div><a href="@Url.Action("ExportCustomers")"> View Crystal Report </a></div>



output





Wednesday, August 9, 2017

How to Play Videos in ASP.NET MVC

Go to Visual Studio

File-> New-Project


The below screen gets displayed. Give any name of the application.

After clicking on ok , the below screen gets displayed: 
Select Empty and select the check box MVC



Let us create a custom action result, Now i have created a Folder with the Name CustomResult inside that i have created a new class File as shown Below



Write the below code in the PlayVideo.cs File 

public class PlayVideo:ActionResult
    {
        public override void ExecuteResult(ControllerContext context)
        {
            //The File Path 
            var videoFilePath = HostingEnvironment.MapPath("~/Videos/big_buck_bunny.mp4");
            //The header information 
            context.HttpContext.Response.AddHeader("Content-Disposition", "attachment; filename=Avent Anniversary.mp4");
            var file = new FileInfo(videoFilePath);
            //Check the file exist,  it will be written into the response 
            if (file.Exists)
            {
                var stream = file.OpenRead();
                var bytesinfile = new byte[stream.Length];
                stream.Read(bytesinfile, 0, (int)file.Length);
                context.HttpContext.Response.BinaryWrite(bytesinfile);
            }
        }
    }

Controller . Create a new controller with the Name VideoController
public class VideoController : Controller
    {
        // GET: Video
        public ActionResult Index()
        {
            return new PlayVideo();
        }
    }

Create a new Index 

Now run the application , Now You can see the below output  



Create another Contoller with the Name 

public class PlayVideoLiveController : Controller
    {
        // GET: PlayVideoLive
        public ActionResult Index()
        {
            return View();
        }
    }

Index.cs.html

<video width="320" height="240" controls autoplay="autoplay">
    <source src="@Url.Action("Index","Video")" type="video/mp4">
    </video>


Output:



Tuesday, August 8, 2017

Working with PDF IN ASP.NET MVC with Entity FrameWork.

With this example you can create pdf and print pdf.

If You are using ASP.NET MVC , PDF can be created by using Rotativa 

Rotativa is a framework that is used to print PDF documents in ASP.NET MVC Applications. This framework we can download using the nuget packages as shown below


Go to Visual Studio

File-> New-Project



The below screen gets displayed. Give any name of the application.


After clicking on ok , the below screen gets displayed: 
Select Empty and select the check box MVC




Let us configure rotative using Nuget as shown below .
Goto to Visual Studio Tools-NuGet Package Manager->Package Manager Console
The below screen gets displayed-> Type the Nuget package command for Rotative




Go to App Data to Add the DataBase as shown below
App Data--->Add--> New Item--> Sql Server DataBase 


In the visual Studio in the solution explorer you can find as shown below

Click on the Open,  the below screen gets displayed  and select New Query and execute the below script  to create the table





Script: 

CREATE TABLE [dbo].[EmployeeInfo] (
    [EmpNo]       INT          IDENTITY (1, 1) NOT NULL,
    [EmpName]     VARCHAR (50) NOT NULL,
    [Salary]      INT          NOT NULL,
    [DeptName]    VARCHAR (50) NOT NULL,
    [Designation] VARCHAR (50) NOT NULL,
    [HRA]         AS           ([Salary]*(0.2)),
    [TA]          AS           ([Salary]*(0.15)),
)

Now the table has been created , 

GoTo Model Folder
Add-->New Item-->ADO.NET Entity Data Model




Give any Name and click on Add, the below screen will be displayed







And Click On Finish

Now goto Contoller Folder and Add New Item


Controller Code:

public class MVCPDFController : Controller
    {
        public ActionResult Index()
        {
            var emps = ctx.EmployeeInfoes.ToList();
            return View(emps);
        }
        EmployeeModel ctx;
        public MVCPDFController()
        {
            ctx = new Models.EmployeeModel();
        }
        public ActionResult PrintAllReports()
        {
            var report = new ActionAsPdf("Index");
            return report;
        }
        public ActionResult PrintPdfDetails(int id)
        {
            var emp = ctx.EmployeeInfoes.Where(e => e.EmpNo == id).First();
            return View(emp);
        }
        public ActionResult PrintSalaryDetails(int id)
        {
            var report = new ActionAsPdf("PrintPdfDetails", new { id = id });
            return report;
        }
    }


Index.cs.html


@model IEnumerable<WebApplication1.Models.EmployeeInfo>
@{
    ViewBag.Title = "Index";
}
<h2>Index</h2>
<p>
    @Html.ActionLink("View In PDF Format", "PrintAllReports")
</p>
<table class="table">
    <tr>
        <th>
            @Html.DisplayNameFor(model => model.EmpName)
        </th>
        <th>
            @Html.DisplayNameFor(model => model.Salary)
        </th>
        <th>
            @Html.DisplayNameFor(model => model.DeptName)
        </th>
        <th>
            @Html.DisplayNameFor(model => model.Designation)
        </th>
        <th></th>
    </tr>
    @foreach (var item in Model)
    {
        <tr>
            <td>
                @Html.DisplayFor(modelItem => item.EmpName)
            </td>
            <td>
                @Html.DisplayFor(modelItem => item.Salary)
            </td>
            <td>
                @Html.DisplayFor(modelItem => item.DeptName)
            </td>
            <td>
                @Html.DisplayFor(modelItem => item.Designation)
            </td>
           
            <td>
                @Html.ActionLink("Print Pay Slip", "PrintSalaryDetails", new { id = item.EmpNo })
            </td>
        </tr>
    }
</table>



PrintPDFDetails.cs.html

@model WebApplication1.Models.EmployeeInfo

@{
    ViewBag.Title = "PrintPdfDetails";
}

<div>
<h2> Salary Details of the Employee : @Model.EmpName 
</h2>
<table>
    <tr>
        <td>Department Name :</td>
        <td>@Model.DeptName</td>
    </tr>
    <tr>
        <td>Designation :</td>
        <td>@Model.Designation</td>
    </tr>
</table>
    <table>
        <tr>
            <td>
                <table>
                    <tr>
                        <td colspan="2">Income Details</td>
                    </tr>
                    <tr>
                        <td>Salary</td>
                        <td>@Model.Salary</td>
                    </tr>
                    <tr>
                        <td>HRA</td>
                        <td>@Model.HRA</td>
                    </tr>
                    <tr>
                        <td>TA</td>
                        <td>@Model.TA</td>

                    </tr>
                </table>
            </td>
        </tr>
    </table>

    <p>
        @Html.ActionLink("Back to Home", "Index")
    </p>
</div>

OutPut


On Clicking on Print Pay Slip



On clicking on View pdf




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