Saturday, February 22, 2014

MVC With CURD Operations

File->New Project




Select Asp.net MVC 3 or MVC4 web application






Select the type of Template as Internet Application
View Engine: Razor

And Click on Ok Button.


Goto Views (Layout.cs.html)





And do the following changes in the code as below screen shot

    <li>@Html.ActionLink("Employee","Employee","Employee")</li>

In the above line

First parameter- Text

Second parameter-Method name or Action Name

Third parameter- Controller Name



Next Go to Model and create a class.










Give the name of the class as Employee.cs
Employees.cs

public class Employees
    {
        public int? Eno { get; set; }

        public string Ename { get; set; }

        public string Address { get; set; }


        public List<Employees> GetAllEmployees()
        {
            DataTable objTbl = new DataTable();
     List<Employees> employeeList = newSystem.Collections.Generic.List<Employees>();
            SqlConnection objCon = new SqlConnection();
            objCon.ConnectionString = "";
            SqlDataAdapter objAdp = new SqlDataAdapter("select * from employees", objCon);
            objAdp.Fill(objTbl);
            foreach (DataRow dr in objTbl.Rows)
            {
                employeeList.Add(new Employee()
                {
                    Eno = Convert.ToInt32(dr["ENO"]),
                    Ename = Convert.ToString(dr["Ename"]),
                    Address = Convert.ToString(dr["Address"])
                });
            }
            return employeeList;
        }
     

    }
Now the model is ready.

Next go to controller.

Add->Controller









And write the following code









Right click on the page




Select Add View






Now the view is created.


And run the application to test the summary Page.





To create:


Write the following lines of code in Employee Controller






Again write click on the controller









And click on Add Button


And run the application.



And click on Create New.



And again write the following lines of code in Employee Controller

[HttpPost]
        public ActionResult Create(Employees obj)
        {
            Employees objemp = new Employees();
            objemp.SaveEmployeeDetails(obj);
            return RedirectToAction("Employee");
        }







And write the following code in Employees.cs

And write the following code in Employees.cs
public void SaveEmployeeDetails(Employees obj)
        {
            SqlConnection objCon = new SqlConnection();
            objCon.ConnectionString = "";
            SqlCommand cmd = new SqlCommand();
            cmd.CommandText = "insert into Employees(Eno,Ename,Address) values(" + obj.Eno + ",'"+ obj.Ename + "','" + obj.Address + "')";
            objCon.Open();
            cmd.Connection = objCon;
            cmd.CommandType = CommandType.Text;
            cmd.ExecuteNonQuery();
            objCon.Close();

        }




Details:


Now go to Employee.cshtml (View Folder)




And modify the following lines of code.

  @Html.ActionLink("Details", "Details", new { id=item.Eno  })


Here Eno is the primary key of my table.





Go to Employee controller.cs

public ActionResult Details(int id)
        {
            Employees obj = Employees.GetEmployeesById(id);
            if (obj == null)
            {
                return HttpNotFound();
            }
            return View(obj);
        }

Go to Employees.cs and write the following code.


  public static Employees GetEmployeesById(int Eno)
        {
            DataTable objTbl = new DataTable();

            SqlConnection objCon = new SqlConnection();
            objCon.ConnectionString = "";

            SqlDataAdapter objAdp = new SqlDataAdapter("select * from employees where eno =" + Eno, objCon);

            objAdp.Fill(objTbl);

            Employees objEmployees = new Employees() { Eno = Convert.ToInt32(objTbl.Rows[0]["Eno"]), Ename = Convert.ToString(objTbl.Rows[0]["Ename"]), Address = Convert.ToString(objTbl.Rows[0]["Address"]) };

            return objEmployees;
        }



And right click on the Employee Controller and select Add View








Edit

Employee.cshtml


@Html.ActionLink("Details", "Details", new { id=item.Eno  }) 





Go to Employee Controller and write the following Code

[HttpGet]
        public ActionResult Edit(int id)
        {
            Employees obj = Employees.GetEmployeesById(id);
            if (obj == null)
            {
                return HttpNotFound();
            }
            return View(obj);
        }




Again Right Click on the Employee Controller and Add View







And click on Add Button.


And test the application.



And click on Edit Button.



Again go to Employee Controller.cs and write the following code to save the modified values.

[HttpPost]
        public ActionResult Edit(Employees obj)
        {
            Employees objemp = new Employees();
            objemp.UpdateEmployeeDetails(obj);
            return RedirectToAction("Employee");


        }






Employees.cs and write the following code


Now update the values and check the summary page.

Delete

Goto Employee.cshtml and modified  the following code .

           @Html.ActionLink("Edit", "Edit", new { id=item.Eno  }) |
            @Html.ActionLink("Details", "Details", new{ id=item.Eno  }) |
            @Html.ActionLink("Delete", "Delete", new { id=item.Eno })

Then go to EmployeeController.cs and write the following code in it.

public ActionResult Delete(int id)
        {
            Employees objemp = new Employees();
            objemp.DeleteEmployeeDetails(id);
            return RedirectToAction("Employee");
        }



Go To Employee.cs and write the following code.



Points to Remember

Here int id in the parameter should be same as
  @Html.ActionLink("Details", "Details", new { id=item.Eno  })

Both the names should be same

Sunday, November 24, 2013

Introduction to JSON

What is JSON

Json Stands JavaScript Object Notation.

JSON is a lightweight text-based open standard data-interchange format.

JSON files are saved with .json extension. Internet media type of JSON is "application/json".

JSON is derived from a subset of JavaScript programming language (Standard ECMA-262 3rd Edition—December 1999).

It is entirely language independent and can be used with most of the modern programming

Similaries between XML & JSON

No end tag like XML
Shorter than XML
Quicker to read and write when compare to XML
Can be parsed using built-in JavaScript functions like eval() and parse()
Uses arrays – Efficient for handling huge data
No reserved words

Data Types in JSON
JSON supports following datatypes:



JSON Syntax


=====================

How to - Solve SQL Server 2012 Identity Problem. Identity increased from 6 to 1000 ............

During application development, we often input dummy data into our database for testing purposes. But then we we want all records of the table to be deleted and also want to start the identity column values from 0. For this, we delete the truncate command. This will delete data from table and also reset the identity column value to 0.

Example
truncate table [table_name]

truncate table product

But truncate command fails to delete the data if there is a relationship given to the table and the identity column is not reset.
So, in this case, first you need to delete data from the child. 

After deleting data, fire this command and it will reset 

your identity column to 0.


DBCC CHECKIDENT('[table_name]', RESEED, [new_reseed_value])

-- for example
DBCC CHECKIDENT('product', RESEED, 0)


Question

Say I have a table which uses an int auto identity as a primary key it is sporadically skipping increments, for example:
1, 2, 3, 4, 5, 1004, 1005

You can use below two choices

Use trace flag 272 , this will cause a log record to be generated for each generated identity value. The performance of identity generation may be impacted by turning on this trace flag.

Solution 1:

     1. Open "SQL Server Configuration Manager"
      2.                Click "SQL Server Services" on the left     pane
     3.                Right-click on your SQL Server instance name on the right pane ->Default: SQL Server(MSSQLSERVER)
    4.               Click "Properties"
    5.                Click "Startup Parameters"
    6.               On the "specify a startup parameter" textbox type "-T272"
   7.               Click "Add"
8.Confirm the changes 










CLICK ON aDD bUTTON

And then restart your sql server.


Use a sequence generator with the NO CACHE setting

solution 2

CREATE SEQUENCE MySeq AS int
  START WITH 1
  INCREMENT BY 1
  NO CACHE;

Friday, November 8, 2013

Installation of SQL SERVER 2012 ( In Windows 8 operating System)

In windows 8 operating system
first install windows 7 service pack1  and then install sql server .

Otherwise u might get an error as sql server cluster fail over




Select New SQL SERVER STAND ALONE INSTALLATION .


Click on Ok


Click on Next


Click on Next


Click on Next Button


Click on Install Button

Click on Next



Click on Next Button




SELECT ALL (Click on SELECT ALL BUTTON) and click on Next Button.



Click on Next Button



Click on Next Button




Server Configuration:
Click on Next Button



select Mixed Mode and enter password.

Click on Add Current User and Click on Next Button





Click on Add Current User and Click on Next



Click on Next Button





Click on Add Current User and Click on Next


Controller Name: leave empty
Click on Next



Click on Next Button
the following screen appears and click on Install.














Kubernetes

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